Giải pt
$x=\sqrt{x-\frac{1}{x}}+\sqrt{1-\frac{1}{x}}$
$\iff x-\sqrt{1-\dfrac{1}{x}}=\sqrt{x-\dfrac{1}{x}}$
$\rightarrow x^2-2\sqrt{x^2-x}+1-\dfrac{1}{x}=x-\dfrac{1}{x}$
$\rightarrow x^2-x-2\sqrt{x^2-x}+1=0$
$\iff \sqrt{x^2-x}=1$
$\iff x^2-x-1=0$
....