Giải phương trình sau:
$\sqrt{\frac{1}{9}+\frac{1}{x}\sqrt{\frac{4}{9}+\frac{2}{x^{2}}}}=\frac{3+x}{x}$
$\sqrt{\frac{1}{9}+\frac{1}{x}\sqrt{\frac{4}{9}+\frac{2}{x^{2}}}}=\frac{3+x}{x}$
Started By nucnt772, 13-08-2013 - 01:17
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