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$4\sqrt{1+2x^{2}y}-1=3x+2\sqrt{1-2x^{2}y}+\sqrt{1-x^{2}} $

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#1
lavie

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Giải hệ phương trình

$\left\{\begin{matrix}

4\sqrt{1+2x^{2}y}-1=3x+2\sqrt{1-2x^{2}y}+\sqrt{1-x^{2}} & \\ 
 2x^{3}y-x^{2}=\sqrt{x^{4}+x^{2}}-2x^{3}y\sqrt{4y^{2}+1}& 
\end{matrix}\right$

Edited by lavie, 11-12-2013 - 07:06.


#2
vuvanquya1nct

vuvanquya1nct

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Giải hệ phương trình

$\left\{\begin{matrix}

4\sqrt{1+2x^{2}y}-1=3x+2\sqrt{1-2x^{2}y}+\sqrt{1-x^{2}} & \\ 
 2x^{3}y-x^{2}=\sqrt{x^{4}+x^{2}}-2x^{3}y\sqrt{4y^{2}+1}& 
\end{matrix}\right$

 

 

$$\left\{\begin{matrix} 4\sqrt{1+2x^{2}y}-1=3x+2\sqrt{1-2x^{2}y}+\sqrt{1-x^{2}} & \\ 2x^{3}y-x^{2}=\sqrt{x^{4}+x^{2}}-2x^{3}y\sqrt{4y^{2}+1}& \end{matrix}\right$$


Edited by vuvanquya1nct, 11-12-2013 - 13:34.

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