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Trung sĩ
$log_{2}(4^x+4)\geq x+log_{2}(2^{x+1}-3)$
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Thiếu úy
Đk: $x> log_{2}3-1$
BPT tương đươg với $log_{2}\frac{4^x+4}{2^{x+1}-3}\geq x \Leftrightarrow \frac{4^x+4}{2.2^x-3}\geq 2^x$
đến đây ta đặt ẩn phụ là xong
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