Tìm a để hệ sau có nghiệm duy nhất:
$\left\{\begin{matrix} \sqrt{x^{2}+2010}+\left | y+1 \right |=a & \\ \left | x \right |\sqrt{y^{2}+2y+2010}=\sqrt{2010-x^{2}}-a& \end{matrix}\right.$
Edited by RoyalMadrid, 23-01-2014 - 21:44.
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