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[thienthanaotrang]

$\left\{\begin{matrix} 2(2x+1)^{3}+2x+1=(2y-3)\sqrt{y-2} & \\ \sqrt{6x+3}+\sqrt{y-10}=4 & \end{matrix}\right.$

[vuvanquya1nct]

$\left\{\begin{matrix} 2(2x+1)^{3}+2x+1=(2y-3)\sqrt{y-2} & \\ \sqrt{6x+3}+\sqrt{y-10}=4 & \end{matrix}\right.$

PT (1) $\Leftrightarrow 2(2x+1)^3+(2x+1)=2(\sqrt{y-2})^3+\sqrt{y-2}$

Dung ham so ta suy ra duoc rang $2x+1=\sqrt{y-2}$ the vao PT(2) la Xong

P/s:tu nhien unikey khong khoi dong cung windown the moi dien !!!