Hệ 1:
$\left\{\begin{matrix} x^{3}+6y^{2}-y^{3}+2x-14y=-12 & \\ \sqrt{3-x}+\sqrt{y-3}=x^{2}+y^{2}-10x-5y+22 & \end{matrix}\right.$
Hệ 2:
$\left\{\begin{matrix} \left ( 4x^{2}+1 \right )x+\left ( y-1 \right )\sqrt{1-2y}=0 & \\4x^{2} +y^{2}+4x+2\sqrt{3-4x}=3 & \end{matrix}\right.$
Edited by phuonglien99, 04-02-2014 - 16:43.