Tìm m để phương trình:
$\sqrt{x+6\sqrt{x-9}}+m\sqrt{x+2\sqrt{x-9}-8}=x+\frac{3m+1}{2}$có hai nghiệm x1,x2 sao cho x1<10<x2
Edited by RoyalMadrid, 01-04-2014 - 20:05.
$\sqrt{x+6\sqrt{x-9}}+m\sqrt{x+2\sqrt{x-9}-8}=x+\frac{3m+1}{2}$
Started By RoyalMadrid, 31-03-2014 - 21:54
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