giải hệ pt sau:
$\left\{\begin{matrix} 2\sqrt{2y^{2}-x^{2}} =y^{2}-2x^{2}+3& \\ x^{3}-2y^{3}=y-2x & \end{matrix}\right.$
$\left\{\begin{matrix} 2\sqrt{2y^{2}-x^{2}} =y^{2}-2x^{2}+3& \\ ... & \end{matrix}\right.$
Started By baotranthaithuy, 06-12-2014 - 15:29
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Posted 06-12-2014 - 15:29
baotranthaithuy
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