$\left\{\begin{matrix}\sqrt{3x+y}-\sqrt{2x-y}=2 & & \\ \sqrt{3x+y}-\sqrt{2y-x}=1 & & \end{matrix}\right.$
M.n giải hộ em với ạ !!!
@MOD: Chú ý tiêu đề
Edited by Viet Hoang 99, 07-12-2014 - 07:55.
$\left\{\begin{matrix}\sqrt{3x+y}-\sqrt{2x-y}=2 & & \\ \sqrt{3x+y}-\sqrt{2y-x}=1 & & \end{matrix}\right.$
Started By sunlowermyn, 06-12-2014 - 21:39
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Posted 06-12-2014 - 21:39
sunlowermyn
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