1 . $\begin{cases}2x-y-xy+\left(y-x-1\right)\sqrt{x-y}=0\\x^2-x+y\sqrt{8y-1}=0\end{cases}$
2.$\begin{cases}x^{3}+y^{3}+2(x+y)=2(x^{2}+y^{2})+x^{2}y^{2}+xy+1 \\ x+y+3=3\sqrt{2y-1} \end{cases}$
3.$\left\{\begin{matrix} \sqrt{x}+\sqrt{4-y}=x^2-y-1 & \\ \sqrt{2(x-y)^2+6x-2y+4}-\sqrt{y}=\sqrt{x+1} & \end{matrix}\right.$
4.$\left\{\begin{matrix} \sqrt{x^{2}-y}=z-1 & \\ \sqrt{y^{2}-z}=x-1& & \\ \sqrt{z^{2}-x}=y-1& & \end{matrix}\right.$
5.$\left\{\begin{matrix}2x^{3}+y^{3}+2x^{2}+y^{2}=xy\left ( 2x+3y+4 \right ) & \\\frac{x^{2}+1}{y}+\frac{y^{2}+1}{x}=\frac{10}{3} & \end{matrix}\right.$
6.$\left\{\begin{matrix} 2x^{2}+xy+y^{2}-4x-y=0 & \\ 4x^{2}+xy+3xy^{2}-x^{2}y-10=0 & \end{matrix}\right.$
7.$\left\{\begin{matrix} x^{2}y+xy-2\sqrt{y}=-1 & \\ 4x^{2}+y^{2}=2x^{2}y^{2}+9 & \end{matrix}\right.$
8.$\left\{\begin{matrix}(x+y)^2+12\sqrt{x+y-6}=4x+3y+37\\ \sqrt{y^2-12}+10\sqrt{y}=x\sqrt{x^2y-5y}+10\end{matrix}\right.$
9.$\left\{\begin{matrix}\sqrt{x+1}-2\sqrt{x}-4\sqrt{y}=y^{2}-3y+5-x\\ 2\sqrt{x+1}-2\sqrt{x}+\sqrt{y}=y\sqrt{x}-\sqrt{y(x+1)}-2y+2 \end{matrix}\right.$
10.$\left\{\begin{matrix}(x+y+3)\sqrt{x-y}+2y+4=0 \\(x-y)(x^{2}+4)=y^{2}+1\end{matrix}\right.$
11.$\left\{\begin{matrix} (x+y^{^{2}})(y-2x)=-6x & & \\3x(x^{_{2}}+y^{2})+y=5x & & \end{matrix}\right.$
12.$\left\{\begin{matrix} x^4-x^3y+x^2y^2=1 & \\ x^3-y-x^2+xy=-1 & \end{matrix}\right.$
13.$\left\{\begin{matrix} x^{2} +xy -3x +y =3 \\ x^{4} +x^2y -5x^2 +y^2 =0 \end{matrix}\right.$
14.$ \left\{\begin{matrix}\ x\sqrt{x^{2}-y^2} + y = 17 & \\ y\sqrt{x^{2}-y^2} -x =7& \end{matrix}\right. $
Bài viết đã được chỉnh sửa nội dung bởi baotranthaithuy: 09-12-2014 - 23:21