Giải hệ phương trình:
$\left\{\begin{matrix} \sqrt{2x}+2\sqrt[4]{6-x}-y^{2}=2\sqrt{2}\\ \sqrt[4]{2x}+2\sqrt{6-x}+2\sqrt{2}y=8+\sqrt{2} \end{matrix}\right.$
(Dùng BĐT)
Edited by rainbow99, 19-01-2015 - 23:39.
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