Giải hệ phương trình:
$\left\{\begin{matrix} x^{2}+y^{2}+xy+1=4y & & \\ (x^{2}+1)(2-x)=x^{2}y & & \end{matrix}\right.$
$\left\{\begin{matrix} x^{2}+y^{2}+xy+1=4y & & \\ (x^{2}+1)(2-x)=x^{2}y & & \end{matrix}\right.$
Started By vanhieu9779, 23-02-2015 - 08:16
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