Giải hệ phương trình $\left\{\begin{matrix} \sqrt{2x}+2\sqrt[4]{6-x}-y^{2}=2\sqrt{2} & \\ \sqrt[4]{2x}+2\sqrt{6-x}+2\sqrt{2}y=8+\sqrt{2} & \end{matrix}\right.$
Giải hệ $\left\{\begin{matrix} \sqrt{2x}+2\sqrt[4]{6-x}-y^{2}=... & \\ ... & \end{matrix}\right.$
Started By Ngoc Hung, 25-03-2015 - 13:06
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