Giải hệ phương trình :
$1)$ $\left\{\begin{matrix}4^{x}+2^{y}=3.(x+y) \\ log_2(3x+2)=5y \end{matrix}\right.$
$2)$ $\left\{\begin{matrix}2^{a^{2}-3ab+b^{2}}=4(a+b+2) \\ log_4(a^{2}+b^{2}) =\frac{1}{2}+log_4(2ab) \end{matrix}\right.$
$\left\{\begin{matrix}4^{x}+2^{y}=3.(x+y) \\ log_2(3x+2)=5y \end{matrix}\right.$
Started By Quoc Tuan Qbdh, 31-07-2015 - 23:35
#1
Posted 31-07-2015 - 23:35
Quoc Tuan Qbdh
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