Ngại gì không thử,yêu cầu ghi rõ cách giải:
1. $x^3+6x+2=2\sqrt{x^{2}(5x-1)}+\sqrt[3]{6x^{2}+x+1}+\sqrt{4x^{3}+4x^{2}+1}$
2. $x^{2}-5x+5=(x-1)\sqrt{3(x^{2}-8x+11)}$
3. $x^{2}+1=(x^{2}-x-1)\sqrt{2x^{2}-3x+5}$
4. $x^{2}-9x+5+x\sqrt{2x^{2}+6}=\sqrt{6x-1}$
5. $4x^{2}+5x+5=(2x+3)\sqrt{3x^{2}+2x+3}$
6. $(\sqrt{x-2}+1)^{3}=\sqrt{x^{3}+3x^{2}+10}$
7. $(\sqrt{1+x}+1)^{3}=\sqrt{x^{3}+2}$
8. $2\sqrt{x^{2}+x+1}+\sqrt{x^{2}+3x+8}=3x+4$
9. $\frac{\sqrt{x-2}}{\sqrt{2x+1}-1}=\frac{1}{\sqrt{x+4}-\sqrt{x-2}}$
10.$\sqrt{x-1}\sqrt[3]{3x+2}+(x^{2}+1)\sqrt{2x+5}-2x^{2}-3x-3=0$
11.$(x^{3}+1\)(\sqrt[3]{2(x+1)})+(x^{2}+2)\sqrt{x-2}=7x^{2}-x+7$
12.$3\sqrt[3]{x}+\sqrt{x^{2}+8}-2=\sqrt{x^{2}+15}$
13.$\sqrt{x+2}+\sqrt{5x+6}+2\sqrt{8x+9}=4x^{2}$
14.$\sqrt[3]{7x-8}+\sqrt{\frac{7-2x^{2}}{6}}=x$