Giải hệ:
$\left\{\begin{matrix}x+\dfrac{3x-y}{x^2+y^2}=3 & \\ y-\dfrac{x+3y}{x^2+y^2}=0& \end{matrix}\right.$
Giải hệ:
$\left\{\begin{matrix}x+\dfrac{3x-y}{x^2+y^2}=3 & \\ y-\dfrac{x+3y}{x^2+y^2}=0& \end{matrix}\right.$
Giải hệ:
$\left\{\begin{matrix}x+\dfrac{3x-y}{x^2+y^2}=3 & \\ y-\dfrac{x+3y}{x^2+y^2}=0& \end{matrix}\right.$
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