$x^{2}+x+2+3x\sqrt{x+1}>0$
$x^{2}+x+2+3x\sqrt{x+1}>0$
Started By mijumaru, 16-02-2016 - 17:29
#1
Posted 16-02-2016 - 17:29
#2
Posted 16-02-2016 - 17:34
$x^{2}+x+2+3x\sqrt{x+1}>0$
$x^3+x^2$ chứ bạn nhỉ ?
#3
Posted 18-02-2016 - 11:17
- leminhnghiatt likes this
#4
Posted 18-02-2016 - 11:23
Ví dụ tôi lỡ tay nhấn vào 1 trích dẫn làm sao xóa đc...
Edited by Tinh1100174, 18-02-2016 - 11:26.
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