Giải Phương trình $\frac{1}{\sqrt{x^2+8}}+\frac{1}{\sqrt{8x^2+1}}=\frac{x-\frac{1}{3}}{x^2}$
$\frac{1}{\sqrt{x^2+8}}+\frac{1}{\sqrt{8x^2+1}}=\frac{x-\frac{1}{3}}{x^2}$
Started By pdtienArsFC, 18-02-2016 - 21:56
1 user(s) are reading this topic
0 members, 1 guests, 0 anonymous users