Giải phương trình:
$(\frac{1}{\sqrt{x-1}}-\frac{\sqrt{x-1}}{x})^2=\frac{4(\sqrt{4x-3}+1)}{\sqrt{x^2+x}+x}$
$(\frac{1}{\sqrt{x-1}}-\frac{\sqrt{x-1}}{x})^2=\frac{4(\sqrt{4x-3}+1)}{\sqrt{x^2+x}+x}$
Started By zzhanamjchjzz, 27-07-2016 - 11:18
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