Giải hệ phương trình $\left\{\begin{matrix}(x+y+1)\sqrt{x-y}+2y+2=0 & & \\ (x^2+2)(x-y-3)=y^2+2 & & \end{matrix}\right.$
$\left\{\begin{matrix}(x+y+1)\sqrt{x-y}+2y+2=0 & & \\ (x^2+2)(x-y-3)=y^2+2 & & \end{matrix}\right.$
Started By chanlerscofield, 31-07-2016 - 15:51
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