2x(y+1)=3+2y(y-1)\\
\sqrt{x^2+y}-x=\dfrac{4+y}{2\sqrt{x^2+y}}
\end{cases}$
Edited by 5S online, 01-11-2016 - 21:33.
$\begin{cases} 2x(y+1)=3+2y(y-1)\\ \sqrt{x^2+y}-x=\dfrac{4+y}{2\sqrt{x^2+y}} \end{cases}$
Started By 5S online, 01-11-2016 - 21:32
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Posted 01-11-2016 - 21:32
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$\begin{cases}
2x(y+1)=3+2y(y-1)\\
\sqrt{x^2+y}-x=\dfrac{4+y}{2\sqrt{x^2+y}}
\end{cases}$
2x(y+1)=3+2y(y-1)\\
\sqrt{x^2+y}-x=\dfrac{4+y}{2\sqrt{x^2+y}}
\end{cases}$
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