Giải pt: $\dfrac{sin{10}x+cos^{10}x}{4}=\dfrac{sin^6x+cos^6x}{4sin^22x+cos^22x}$
Edited by chieckhantiennu, 16-12-2016 - 10:58.
Giải pt: $\dfrac{sin{10}x+cos^{10}x}{4}=\dfrac{sin^6x+cos^6x}{4sin^22x+cos^22x}$
Started By chieckhantiennu, 16-12-2016 - 10:32
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Posted 16-12-2016 - 10:32
chieckhantiennu
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