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Sĩ quan
$\mathbb{VTL}$
Câu bất
a) (1)$\Leftrightarrow$ 6/a2+6/b2+6/c2$\leq$1/a+1/b+1/c+1
$\Leftrightarrow$ 2(1/a+1/b+1/c)2-(1/a+1/b+1/c)-1$\leq$0
$\Leftrightarrow$ (1/a+1/b+1/c-1)(2/a+2/b+2/c+1$\leq$)0
$\Leftrightarrow$1/a+1/b+1/c$\leq$1
b)
M$\leq$1/12.(1/a+1/b+1/c)$\leq$1/12
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