$(x^{2}+2)\sqrt{x^{2}+x+1}+x^{3}-3x^{2}-5x+2=0$
$(x^{2}+2)\sqrt{x^{2}+x+1}+x^{3}-3x^{2}-5x+2=0$
Started By Tri369, 20-07-2017 - 16:30
#1
Posted 20-07-2017 - 16:30
#2
Posted 20-07-2017 - 19:44
$(x^{2}+2)\sqrt{x^{2}+x+1}+x^{3}-3x^{2}-5x+2=0$
PT$\Leftrightarrow ({{x}^{2}}+2)(\sqrt{{{x}^{2}}+x+1}-2)+({{x}^{3}}-{{x}^{2}}-5x+6)=0$
$\Leftrightarrow ({{x}^{2}}+2)(\sqrt{{{x}^{2}}+x+1}-2)+(x-2)({{x}^{2}}+x-3)=0$
$\Leftrightarrow {{x}^{2}}+x-3=0$ hoặc $ (x-2)\sqrt{{{x}^{2}}+x+1}={{x}^{2}}+2x-2$
Edited by NAT, 20-07-2017 - 19:45.
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