Tính: $\int x.\frac{ln\left (\frac{1+x}{1-x} \right )}{(x-1)^2}dx$
$\int x.\frac{ln\left (\frac{1+x}{1-x} \right )}{(x-1)^2}dx$
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Started By Truong Gia Bao, 20-07-2017 - 20:39
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