Tính $S= \sum_{k=1}^{n} \frac{(-1)^{k}kC_{n}^{k}}{(k+1)(k+2)}$
Tính $S= \sum_{k=1}^{n} \frac{(-1)^{k}kC_{n}^{k}}{(k+1)(k+2)}$
Started By hieu31320001, 12-02-2018 - 00:40
#1
Posted 12-02-2018 - 00:40
Knowing both victory and defeat.That is the way you become a real man-Shanks
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