1)$x\sqrt{x+\sqrt{x}}-\sqrt{x-\sqrt{x}}=\frac{3}{2}\sqrt{\frac{x}{x+\sqrt{x}}}$
2)$x^3+6x^2+12x=2\sqrt[3]{4x+3}+9$
1)$x\sqrt{x+\sqrt{x}}-\sqrt{x-\sqrt{x}}=\frac{3}{2}\sqrt{\frac{x}{x+\sqrt{x}}}$
2)$x^3+6x^2+12x=2\sqrt[3]{4x+3}+9$
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