Chưa có bài trả lời

[vannamdn]

Giải Phương trình
$1) 2sin4x+4sinx+1=4\sqrt[]{2}sin(\dfrac{5x}{2})cos(\dfrac{x}{2}-\dfrac{\pi}{4})$
$2) (1+\sqrt[]{3})sin(2x+\dfrac{\pi}{4})=2\sqrt[]{2}(cos(x-\dfrac{\pi}{3})-sin^2x)$
$3) \dfrac{sin(\dfrac{\pi}{3})}{sinx}+tanx=$$\dfrac{cos(\dfrac{\pi}{4})}{cosx}+cotx+1$
$4) 6sinx-cos^3x=5sin2xcos^2x$