a){3^x} + {4^x} < {5^x} \\
b)x + \sqrt {x + \dfrac{1}{2} + \sqrt {x + \dfrac{1}{4}} } > a \\
c)\dfrac{{\left| {4 - x} \right|}}{{x + 6}} < 3 \\
d)\sqrt[3]{{2 - x}} + \sqrt {x - 1} > 1 \\
$
Edited by my_ha_123, 03-11-2010 - 20:09.
Edited by my_ha_123, 03-11-2010 - 20:09.
Em không bỏ được <br/> hjx$
a){3^x} + {4^x} < {5^x} \\
b)x + \sqrt {x + \dfrac{1}{2} + \sqrt {x + \dfrac{1}{4}} } > a \\
c)\dfrac{{\left| {4 - x} \right|}}{{x + 6}} < 3 \\
d)\sqrt[3]{{2 - x}} + \sqrt {x - 1} > 1 \\
$
$\begin{matrix} &a)& {3^x} + {4^x} < {5^x} \\ &b)& x + \sqrt {x + \dfrac{1}{2} + \sqrt {x + \dfrac{1}{4}} } > a \\ &c)& \dfrac{{\left| {4 - x} \right|}}{{x + 6}} < 3 \\ &d)& \sqrt[3]{{2 - x}} + \sqrt {x - 1} > 1 \end{matrix}$
Edited by novae, 03-11-2010 - 20:32.
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