We need more posts in this topic, I thinks
Now let's discuss the followings:
1) Let M and N be nilpotent subgroups of a group G. Give an example to show that when M and N are not both normal in G, the group MN need not be nilpotent.
2) Let M and N be solvable subgroups of a group G. Give an example to show that when both M and N are not normal in G, the group MN need not be solvable.
I expect answers from everyone !
Solvable and Nilpotent groups
Bắt đầu bởi nemo, 16-10-2005 - 21:14
#1
Đã gửi 16-10-2005 - 21:14
<span style='color:purple'>Cây nghiêng không sợ chết đứng !</span>
#2
Đã gửi 18-10-2005 - 10:13
What is your definition of http://dientuvietnam.../mimetex.cgi?MN when both http://dientuvietnam...n/mimetex.cgi?M and http://dientuvietnam...n/mimetex.cgi?N are not normal subgroups of http://dientuvietnam.../mimetex.cgi?G?
<span style='color:blue'>Thu đi để lại lá vàng
Anh đi để lại cho nàng thằng ku</span>
Anh đi để lại cho nàng thằng ku</span>
#3
Đã gửi 20-10-2005 - 09:06
Definition of MN is MN={mn | m M, n N}. We have, if H is a normal subgroup and K is a subgroup of a group G then HK be a subgroup of G but it is not equivalent (!?) (I am not sure ).
<span style='color:purple'>Cây nghiêng không sợ chết đứng !</span>
#4
Đã gửi 13-12-2005 - 00:02
Let M a compact complex Lie group, U a complex lie subgroup and biholomorph to http://dientuvietnam.net/cgi-bin/mimetex.cgi?\mathbb{C}^n. Question: Is U nilpotent?
Bài viết đã được chỉnh sửa nội dung bởi quantum-cohomology: 13-12-2005 - 00:03
#5
Đã gửi 02-05-2006 - 15:58
Like canh_dieu I don't know what MN will be when M and N are not both normal in G.
I just give an example :" Let M and N be nilpotent subgroups of a group G. Give an example to show that when M normal in G, N is not normal in G, the group MN need not be nilpotent"
We have known that S_3 is not nipoten because Z(S_3)=1.
for n 4 then 1, A_n are the only normal subgroups of S_n .
Let :
C(3)=<(123)>=A_3 then |C(3)|=3 then C(3) is nilpotent
C(2)=<(12)>= then |C(2)|=2 then C(2) is nilpotent and not normal in S_3.
Since C(3) C(2)=1 so we have S_3=C(2)C(3)
I just give an example :" Let M and N be nilpotent subgroups of a group G. Give an example to show that when M normal in G, N is not normal in G, the group MN need not be nilpotent"
We have known that S_3 is not nipoten because Z(S_3)=1.
for n 4 then 1, A_n are the only normal subgroups of S_n .
Let :
C(3)=<(123)>=A_3 then |C(3)|=3 then C(3) is nilpotent
C(2)=<(12)>= then |C(2)|=2 then C(2) is nilpotent and not normal in S_3.
Since C(3) C(2)=1 so we have S_3=C(2)C(3)
Reserve your right to think, for even to think wrongly is better than not to think at all -Hypatia- A woman Mathematician
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