x+y+z=xyz\\ x(y^{2}-1)(z^{2}-1)+y(x^{2}-1)(z^{2}-1)+z(x^{2}-1)(y^{2}-1)=0
\end{matrix}\right.$$
Edited by YenThanh2, 15-07-2012 - 08:42.
Edited by YenThanh2, 15-07-2012 - 08:42.
Ta có:$$\left\{\begin{matrix}
x+y+z=xyz\\ x(y^{2}-1)(z^{2}-1)+y(x^{2}-1)(z^{2}-1)+z(x^{2}-1)(y^{2}-1)=0
\end{matrix}\right.$$
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