GHPT:
Bài 1:
$\begin{cases} 4\sqrt{x+1} = y -x+4 \\ \dfrac{4xy}{x-y} +2\sqrt[3]{x^{2} -y^{2}} =1 \end{cases}$
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Bài 2:
$\begin{cases}
& {z}^{2}+2xyz=1 \\
& 3{x}^{2}{y}^{2}+3{y}^{2}x=1+{x}^{3}{y}^{4} \\
& z+z{y}^{4}+4{y}^{3}=4y+6{y}^{2}z
\end{cases}$
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Bài 3:
$\begin{cases}
& 2z+1={x}^{3}+{x}^{2}+x \\
& 2y+1={z}^{3}+{z}^{2}+z \\
& 2x+1= {y}^{3}+{y}^{2}+y
\end{cases}$
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Bài 4:
$\left\{\begin{matrix}2{x}^{3}+{x}^{2}y+(x+\dfrac{y}{2})^{2}={y}^{3}-\dfrac{3{y}^{2}}{4}
\\ \sqrt{x+2} +\sqrt{2y-1}=5
\end{matrix}\right.$
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Bài 5:
$\left\{\begin{matrix}
x\sqrt{y+1}+y\sqrt{x+1}=3 & \\
\frac{6{(x+y)}^{2}}{xy}+{x}^{2}+{y}^{2}-5(x+y)=\frac{2{x}^{2}}{y}+\frac{3{y}^{2}}{x}+6 &
\end{matrix}\right.$
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Bài 6:
$\begin{cases}x^4+x^2+xy(x^2-2x-y)=-2\\ 2(x^2-y)-xy(2x^2-2y+1)=5 \end{cases}$
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Bài 7:
$\left\{\begin{matrix}
2\sqrt{{x}^{2}+y} -\sqrt{{y}^{2}+8x}=1& \\x(x+8)+y(y+3)=13
&
\end{matrix}\right.$
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Bài 8:
\[\begin{cases}\left( x-\sqrt{{{y}^{2}}-1} \right)\left( y+\sqrt{{{x}^{2}}-1} \right)=1 \\ \sqrt{3x+y+1}-\sqrt{x+y}=1 \end{cases}\]
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Bài 9:
$\left\{\begin{matrix} \sqrt{x+3y+1}+\sqrt{8x+y+1}+\frac{1}{2012y}=\sqrt{4y+1}+\sqrt{9x+1}+\frac{1}{2012x}\\ x-y^2=\frac{4}{81} \end{matrix}\right.$
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Bài 10:
$\left\{\begin{matrix} y^{3}+3xy^{2}=-14 & \\ x^{2}-xy+y^{2}=2x-\frac{5}{2y} & \end{matrix}\right.$
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Bài 11:
$\left\{\begin{matrix}
{x}^{2}+{y}^{2}=1& \\
\sqrt[2011]{x} -\sqrt[2011]{y}=(\sqrt[2012]{x}-\sqrt[2012]{y})(x+y+xy+2013)&
\end{matrix}\right.$
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Bài 12:
$\left\{ \begin{array}{l} {x^6} - {y^3} + {x^2} - 9{y^2} - 30 = 28y\\ 2(\sqrt x - \sqrt {x - 1} )(1 + \sqrt {y + 2} ) = \sqrt {x(y + 3)} \end{array} \right.$
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Bài 13:
\[\begin{cases} 2x^{2}+xy+y=5\\ y^{2}+2xy+5x=7 \end{cases}\]
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Bài 14:
$\left\{\begin{matrix}
{y}^{3}(27{x}^{3}-35)+8=0 & \\
3{x}^{2}y+2x=5{y}^{2} &
\end{matrix}\right.$
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(Trích Boxmath)
Bài viết đã được chỉnh sửa nội dung bởi minhdat881439: 10-08-2012 - 20:34