Edited by Tham Lang, 26-09-2012 - 17:08.
Giải phương trình sau: $(\frac{1}{x^2+x+2})^2+(\frac{1}{x^2+x+2})^2=\frac{13}{16}$
Started By anhxuanfarastar, 26-09-2012 - 16:12
#1
Posted 26-09-2012 - 16:12
Giải phương trình sau: $(\frac{1}{x^2+x+1})^2+(\frac{1}{x^2+x+2})^2=\frac{13}{16}$
INTELLIGENCE IS THE ABILITY TO ADAPT TO CHANGE !!!
#2
Posted 26-09-2012 - 16:14
Có bị nhầm không vây?Giải phương trình sau: $(\frac{1}{x^2+x+2})^2+(\frac{1}{x^2+x+2})^2=\frac{13}{16}$
Edited by traitimcamk7a, 26-09-2012 - 16:16.
1 user(s) are reading this topic
0 members, 1 guests, 0 anonymous users