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tuyen1481999
#669720 Bài 1: Tìm GTNN của: $P=\frac{1344}{a+\sqrt...
Posted by
on 24-01-2017 - 17:11
#654097 Tính: $A=\frac{2^{1}C_{2011}^{0}...
Posted by
on 14-09-2016 - 00:50
Tính:
$A=\frac{2^{1}C_{2011}^{0}}{1.2}-\frac{2^{2}C_{2011}^{1}}{2.3}+\frac{2^{3}C_{2011}^{2}}{3.4}-\frac{2^{4}C_{2011}^{3}}{4.5}+...+\frac{2^{2011}C_{2011}^{2010}}{2011.2012}-\frac{2^{2012}C_{2011}^{2011}}{2012.2013}$
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