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$\frac{a}{2-a}+\frac{1-a}{1+a}=\frac{a}{2-a}+1+\frac{1-a}{1+a}+1-2 =\frac{2}{2-a}+\frac{2}{1+a}-2 \geq \frac{8}{2+a+1-a}-2=\frac{2}{3}$
min T=2/3 khi a=0,5
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zack william
#709536 [TOPIC] $\text{Luyện đề ôn thi} $ $\boxed{\text...
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on 29-05-2018 - 22:26
