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CM tồn tại $c\in (0,1)$ sao cho $f'(c)=2022f(c)$
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Nguyên hàm đa biến
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$\left\{\begin{matrix}4x^2=(\sqrt{x^2+1}+1)(x^2-y^3+3y-2) & \\ x^2+(y+1)^2 =2\left ( 1+\frac{1-x^2}{y} \right )& \end{matrix}\right.$
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ĐỀ THI VÀO 10 CHUYÊN TOÁN TRẦN PHÚ - HẢI PHÒNG NĂM HỌC 2018-2019
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$f(2x)=2f(x)$ và $f(f^2(x))=xf(x)$
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