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$\sum\frac{a}{\sqrt{2a+b+3c}}<\sqrt{\frac{8}{15}(a+b+c)}$


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Strygwyr

Strygwyr

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Bài toán :

Cho các số thực không âm $a$,$b$,$c$. Chứng minh rằng :

$\frac{a}{\sqrt{2a+b+3c}}+\frac{b}{\sqrt{2b+c+3a}}+\frac{c}{\sqrt{2c+a+3b}}<\sqrt{\frac{8}{15}(a+b+c)}$

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"Nothing is impossible"

(Napoleon Bonaparte)





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