Cho a,b,c >0 thỏa 2013ac + ab + bc = 2013
Tìm max P = $\frac{2}{a^2+1}-\frac{2b^2}{b^2+2013^2}+\frac{3}{c^2+1}$
Tìm max P = $\frac{2}{a^2+1}-\frac{2b^2}{b^2+2013^2}+\frac{3}{c^2+1}$
Started By beontop97, 24-09-2013 - 19:14
#1
Posted 24-09-2013 - 19:14
beontop97
-
- Thành viên
-
- 56 posts
Hạ sĩ
1 user(s) are reading this topic
0 members, 1 guests, 0 anonymous users
