Cho các số thực dương $a,b,c$ thỏa mãn $a^2 + b^2 +c^2 =1$. Chứng minh:
$\frac{1}{1-ab}+\frac{1}{1-bc}+ \frac{1}{1-ac}\leq \frac{9}{2}$
Chứng minh : $\frac{1}{1-ab}+\frac{1}{1-bc}+ \frac{1}{1-ac}\leq \frac{9}{2}$
Started By orchid96, 24-10-2013 - 21:20
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