Với $a,b,c$ dương; $a+b+c=3$.Chứng minh:
$\frac{1}{1+ab}+\frac{1}{1+bc}+\frac{1}{1+ca}\geq \frac{9}{2(\sqrt{a}+\sqrt{b}+\sqrt{c})}$
$\frac{1}{1+ab}+\frac{1}{1+bc}+\frac{1}{1+ca}\geq \frac{9}{2(\sqrt{a}+\sqrt{b}+\sqrt{c})}$
Started By VNSTaipro, 05-11-2013 - 16:14
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Posted 05-11-2013 - 16:14
VNSTaipro
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