$\left\{\begin{matrix} 2y^{3}-(x+4)y^{2}+8y+x^{2}-4x=0 & & \\ \sqrt{(1-x)/2}+\sqrt{x+2y+3}=4(x-1)^{2}+8y-1/2& & \end{matrix}\right.$
$\left\{\begin{matrix} 2y^{3}-(x+4)y^{2}+8y+x^{2}-4x=0 & & \\
Started By ZzZzZzZzZ, 07-02-2014 - 20:01
#2
Posted 07-02-2014 - 20:21
$\left\{\begin{matrix} 2y^{3}-(x+4)y^{2}+8y+x^{2}-4x=0 & & \\ \sqrt{(1-x)/2}+\sqrt{x+2y+3}=4(x-1)^{2}+8y-1/2& & \end{matrix}\right.$
PT 1 tuong duong
$x^2-x(y^2+4)+2y^3-4y^2+8y=0$
Ta co $\Delta =(y+2)^4$
OK
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