Cho a,b,c>0 thoả a+b+c=3
Chứng minh :
$\sqrt{a^3b(ab+2b^2)}+\sqrt{b^3c(bc+2c^2)}+\sqrt{c^3a(ca+2b^2)}$$\leq 3\sqrt{3}$
$\sqrt{a^3b(ab+2b^2)}+\sqrt{b^3c(bc+2c^2)}+\sqrt{c^3a(ca+2b^2)}$$\leq 3\sqrt{3}$
Started By beontop97, 17-10-2014 - 13:57
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