Cho $a^{2003}+b^{2003}=a^{2004}+b^{2004}=a^{2005}+b^{2005}$. Tính $a^{2006}+b^{2006}$
Edited by Mikhail Leptchinski, 28-06-2015 - 00:54.
$a^{2003}+b^{2003}=a^{2004}+b^{2004}=a^{2005}+b^{2005}$
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Started By Sherlock Homes, 27-06-2015 - 20:39
#1
Posted 27-06-2015 - 20:39
Sherlock Homes
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Impossible is nothing --- ADDIDAS ---
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#2
Posted 27-06-2015 - 20:47
rainbow99
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Cho a2003+b2003=a2004+b2004=a2005+b2005. Tính a2006+b2006
Ta có: $(a^{2003}+b^{2003})(a^{2005}+b^{2005})=(a^{2004}+b^{2004})^{2}$
Đến đây phân tích ra là được.
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