Cho $a,b,c$ thực dương thỏa $a\leq b\leq c$ và $abc=1$.Chứng minh rằng:
$a+b^2+c^3\geq \frac{1}{a}+\frac{1}{b^2}+\frac{1}{c^3}$
$a+b^2+c^3\geq \frac{1}{a}+\frac{1}{b^2}+\frac{1}{c^3}$
Started By binhnhaukhong, 11-07-2015 - 08:39
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