Cho $\Delta ABC$ . Tìm Max :
$$P=\dfrac{\dfrac{\sqrt{3}}{2}sin\dfrac{A}{2}sin\dfrac{B}{2}}{4\sqrt{1+\dfrac{5}{sin\dfrac{C}{2}}}-1}$$
Các bạn trình bày hướng làm nhá (Đáp án mình có rồi 
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Edited by JayVuTF, 23-08-2015 - 08:13.
$\dfrac{\dfrac{\sqrt{3}}{2}sin\dfrac{A}{2}sin\dfrac{B}{2}}{4\sqrt{1+...}}$
Started By JayVuTF, 23-08-2015 - 08:06
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Posted 23-08-2015 - 08:06
JayVuTF
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