Cho a,b,c thuộc [0;2] ,$a+b+c=3$
Tìm Min của:
$P=\frac{2}{11-a^2-b^2-c^2}-\frac{a^3+b^3+c^3}{ab+bc+ca+5}$
$P=\frac{2}{11-a^2-b^2-c^2}-\frac{a^3+b^3+c^3}{ab+bc+ca+5}$
Started By quanghao98, 16-12-2015 - 12:37
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Posted 16-12-2015 - 12:37
quanghao98
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