CMR $N = \frac{1}{7^{2}} - \frac{1}{7^{4}} + \frac{1}{7^{6}} -....+ \frac{1}{7^{98}} - \frac{1}{7^{100}} < \frac{1}{50}$
1 user(s) are reading this topic
0 members, 1 guests, 0 anonymous users
Community Forum Software by IP.Board
Licensed to: Diễn đàn Toán học
