Cho các số dương x,y,z thỏa mãn: $x+z\leq 2y$ , $x^{2}+y^{2}+z^{2}=1$ . Tìm GTLN của:
$P=\frac{xy}{1+z^{2}}+\frac{yz}{1+x^{2}}-y^{3}(\frac{1}{x^{3}}+\frac{1}{z^{3}})$
$P=\frac{xy}{1+z^{2}}+\frac{yz}{1+x^{2}}-y^{3}(\frac{1}{x^{3}}+\frac{1}{z^{3}})$
Started By Love Math forever, 21-06-2016 - 10:36
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