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Xét bt: A = $\frac{a^{2}+\sqrt{a}}{a-\sqrt{a}+1}$ - $\frac{2a+\sqrt{a}}{\sqrt{a}}$ + 1

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#1
youaremyfriend

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Xét bt:

  A = $\frac{a^{2}+\sqrt{a}}{a-\sqrt{a}+1}$ $-$ $\frac{2a+\sqrt{a}}{\sqrt{a}}$ + 1

 Tìm min của A


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#2
12345678987654321123456789

12345678987654321123456789

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Rút gọn được $A=a-\sqrt{a}=\left(\sqrt{a}-\frac{1}{2}\right)^2-\frac{1}{4}\geq-\frac{1}{4}$

Dấu "=" xảy ra khi và chỉ khi $a=\frac14$


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#3
thinhnarutop

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Ta có: $A=a-\sqrt{a}=(\sqrt{a}-\frac{1}{2})^{2}-\frac{1}{4}\geq \frac{-1}{4}$

Dấu = xảy ra <=> a = 1/4


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